Question

ДАМ 100б памагите со всем​

Answer 1

1) C

2) $\frac{4}{9}$; $1\frac{1}{3}$; $2\frac{5}{6}$; $\frac{20}{3}$

3) $x=\frac{14}{21}$

4) $\frac{24}{29}\\$ кг

5) $\frac{163}{216}$

Пошаговое объяснение:

2) 4/3; 20/3; 17/6; 4/9 | 24/18; 120/18; 51/18; 8/18 | 8/18; 24/18; 51/18; 120/18

3) $x+\frac{2}{21}-\frac{11}{21}=\frac{5}{21} \\\\x=\frac{5}{21}-\frac{2}{21}+\frac{11}{21}\\\\x=\frac{14}{21}$

4) $\frac{5}{8}+\frac{1}{6}+x=2\\\\\frac{15}{24}+\frac{4}{24}+\frac{24x}{24}=\frac{48}{24}\\15+4+24x=48\\24x=48-15-4\\24x=29\\x=\frac{29}{24}$

5)$(3\frac{5}{6}-1\frac{3}{4}):(5\frac{1}{8}+4\frac{7}{24})+(1\frac{1}{5}+2\frac{1}{6}+1\frac{19}{30})*\frac{1}{10}=\frac{\frac{23}{6}-\frac{7}{4}}{\frac{41}{8}+\frac{103}{24}}+(\frac{6}{5}+\frac{13}{6}+\frac{49}{30})*\frac{1}{10}=\frac{\frac{46}{12}-\frac{21}{12}}{\frac{123}{24}+\frac{103}{24}}+(\frac{36}{30}+\frac{65}{30}+\frac{49}{30})*\frac{1}{10}=\frac{\frac{25}{12}}{\frac{226}{24}}+(\frac{36}{30}+\frac{65}{30}+\frac{49}{30})*\frac{1}{10}=\frac{25*24}{12*226}+\frac{150}{30}*\frac{1}{10}$$\frac{25*24}{12*226}+\frac{150}{30}*\frac{1}{10}=\frac{50}{226}+\frac{5}{10}=\frac{50}{226}+\frac{1}{2}=\frac{50}{226}+\frac{113}{216}=\frac{163}{216}$