Question

Отдам все свои кровны! но решите это дерьмо!

Answer 1

1)

$(\frac{6}{5}-\frac{3}{4})*\frac{2}{3}= (\frac{24}{20}-\frac{15}{20})*\frac{2}{3} =\frac{9}{20}*\frac{2}{3}=\frac{3}{10}*\frac{1}{1}=\frac{3}{10} =0,3$

2)

$(\frac{6}{5}-\frac{2}{3})*\frac{1}{2}=(\frac{18}{15}-\frac{10}{15})*\frac{1}{2}=\frac{8}{15}*\frac{1}{2} =\frac{4}{15} *\frac{1}{1}=\frac{4}{15}$

3)

$\frac{11}{18}-\frac{4}{9}*\frac{3}{16}=\frac{11}{18}-\frac{1}{3}*\frac{1}{4}=\frac{11}{18}-\frac{1}{12}= \frac{22}{36}-\frac{3}{36} =\frac{19}{36}$

4)

$\frac{29}{30}-\frac{5}{18}*\frac{6}{25}= \frac{29}{30}-\frac{1}{3}*\frac{1}{5}= \frac{29}{30}-\frac{1}{15}= \frac{29}{30}-\frac{2}{15}=\frac{27}{30}=\frac{9}{10}$

5)

$\frac{8}{5}*(\frac{3}{4}+\frac{11}{8})= \frac{8}{5}*(\frac{6}{8}+\frac{11}{8})= \frac{8}{5}*\frac{17}{8}=\frac{17}{8}= 2\frac{1}{8}$

6)

$\frac{18}{7}*(\frac{4}{9}+\frac{15}{18})= \frac{18}{7}*(\frac{8}{18}+\frac{15}{18})= \frac{18}{7}*\frac{23}{18}=\frac{23}{7}=3\frac{2}{7}$

7)

$\frac{8}{5}*\frac{3}{4}+\frac{11}{8}= \frac{2}{5}*\frac{3}{1}+\frac{11}{8}=\frac{6}{5}+\frac{11}{8}=\frac{48}{40}+\frac{55}{40}=\frac{103}{40}=2\frac{23}{40}$

8)

$- \frac{1}{3}*\frac{6}{5}-\frac{5}{6}*\frac{3}{25}= - \frac{1}{1}*\frac{2}{5}-\frac{1}{2}*\frac{1}{5}=-\frac{2}{5}-\frac{1}{10}=-\frac{4}{10}-\frac{1}{10}=-\frac{5}{10}=-0,5$

9)

$\frac{18}{7}*\frac{4}{9}+\frac{15}{14}= \frac{2}{7}*\frac{4}{1}+\frac{15}{14}=\frac{8}{7}+\frac{15}{14}=\frac{16}{14}+\frac{15}{14}=\frac{31}{14}=2\frac{3}{14}\\$

10)

$- \frac{1}{4}*\frac{8}{6}-\frac{7}{18}*\frac{9}{21}=- \frac{1}{1}*\frac{2}{5}-\frac{1}{2}*\frac{1}{3}=-\frac{2}{5}-\frac{1}{5}=-\frac{1}{5}$