Question

1) (15-9 1/3) : 2/3 2) (19 2/3-11 7/9) : 9/71
3) 1) : 2) - 8 45/100=?

Answer 1

1.

$(15 - 9 \frac{1}{3} ) \div \frac{2}{3}$

$1)15 - 9 \frac{1}{3} = 14 \frac{3}{3} - 9 \frac{1}{3 } = 5 \frac{2}{3}$

$2)5 \frac{2}{3} \div \frac{2}{3} = \frac{17}{3} \div \frac{2}{3} = \frac{17 \times 3}{3 \times 2} = \frac{17}{2} = 8 \frac{1}{2}$

2.

$(19 \frac{2}{3} - 11 \frac{7}{9} ) \div \frac{9}{71}$

$19 \frac{2}{3} - 11 \frac{7}{9} = \frac{59}{3} ^{3} - \frac{106}{9} = \frac{177 - 106}{9} = \frac{71}{9} = 7 \frac{8}{9}$

$7 \frac{8}{9} \div \frac{9}{71} = \frac{71}{9} \div \frac{9}{71} = \frac{71 \times 71}{9 \times 9} = \frac{5041}{81} = 62 \frac{19}{81}$