Question

Решите уравнение: а) б)24,8: (6,08x-20,8)*2,7=1,674

Answer 1

a) $\frac{27*43}{43}-\frac{43+10}{43}-\frac{5*43+39}{43}+x-\frac{6*43+27}{43}=\frac{43*20+2}{43}$

$\frac{1161}{43}-\frac{53}{43}-\frac{254}{43}-\frac{285}{43}-\frac{862}{43}+x=0$

$\frac{1161-53-254-285-862}{43}+x=0$

$\frac{-293}{43}+x=0$

$x=\frac{293}{43}$.

б) $24.8:(6.08x-20.8)=\frac{1.674}{2.7}$

$\frac{24.8}{6.08x-20.8}=0.62$

$\frac{1}{6.08x-20.8}=0.025$

$6.08x-20.8=\frac{1}{0.025}$

$6.08x=40+20.8$
$6.08x=60.8$
$x=10$

Answer 2

27*43/43-(1*43+10)/43- (5*43+39)/43 +х*43/43-(6*43+27)/43=(20*43+2)/43

1161/43-53/43-254/43+43х/43-285/43=862/43

1161-53-254+43х-285=862

569+43х=862

43х=862-569

43х=293

х=293/43

х=6 целых 35/43 не знаю, где здесь математический редактор

24,8*2,7/(6,08х-20,8)=1,674

66,96/(6,08х-20,8)=1,674

(6,08х-20,8)=66,96/1,674

6,08х-20,8=40

6,08х=40+20,8

6,08х=60,8

х=60,8/6,08=6080/608

х=10