Question

Можно в черновике найдите значения выражений: 1)0,75a-b:8 1/11 при а=11 1/3 и b=8,9; 2)15 1/6:х+0,13у при х=18,2 и у=7 1/13; 3)n:21 6/23-1/47m при n=97,8 и m=31 1/3; 4)с:1 2/3+d:8 15/19 при с=67 1/7 и d=33,4​

Answer 1

1)

$0,75a-b:8\frac{1}{11} =0,75*11\frac{1}{3} -8,9:8\frac{1}{11} =\frac{3}{4} *11\frac{1}{3} -8\frac{9}{10} :8\frac{1}{11}=\\ \\ \frac{3}{4} *\frac{34}{3} -\frac{89}{10} *\frac{11}{89}=\frac{17}{2} -\frac{11}{10} =8,5-1,1=7,4$

2)

$15\frac{1}{6} :x+0,13y=15\frac{1}{6} :18,2+0,13*7\frac{1}{13} =\frac{91}{6} :18\frac{1}{5} +\frac{13}{100} *7\frac{1}{13}=\\ \\ \frac{91}{6}*\frac{5}{91} +\frac{13}{100} *\frac{92}{13}=\frac{5}{6} +\frac{23}{25} =\frac{125}{150} +\frac{138}{150} =\frac{263}{150} =1\frac{113}{150}$

3)

$n:21\frac{6}{23} -\frac{1}{47} m=97,8:\frac{489}{23} -\frac{1}{47} *31\frac{1}{3} =\\ \\ 97\frac{4}{5} *\frac{23}{489} -\frac{1}{47} *\frac{94}{3} =\frac{489}{5} *\frac{23}{489} -\frac{1}{47} *\frac{94}{3}=\frac{23}{5} -\frac{2}{3} =4\frac{3}{5} -\frac{2}{3}=\\ \\ 4\frac{9}{15} -\frac{10}{15} =3\frac{14}{15}$

4)

$c:1\frac{2}{3} +d:8\frac{15}{19} =67\frac{1}{7} :1\frac{2}{3} +33,4:8\frac{15}{19} =\\ \\ \frac{470}{7} *\frac{3}{5} +\frac{167}{5} *\frac{19}{167} =\frac{282}{7} +\frac{19}{5} =40\frac{2}{7} +3\frac{4}{5} =40\frac{10}{35} +3\frac{28}{35} =43\frac{38}{35} =44\frac{3}{35}$