Question

14/45-(12/45+1/45)=? 70/190-(15/190+20/190)=?
6/12+(5/12-1/12)=?
121/300-(10/300+90/300)=?
43/100-(25/100+17/100)=?
у меня мало ..никто на вопрос не ответит(​

Answer 1

$1) \frac{14}{45} - ( \frac{12}{45} + \frac{1}{45} ) = \frac{14}{45} - ( \frac{12 + 1}{45} ) = \frac{14}{45} - \frac{13}{45} = \frac{14 - 13}{45} = \frac{1}{45}$

$2) \frac{70}{190} - ( \frac{15}{190} + \frac{20}{190} ) = \frac{70}{190} - ( \frac{15 + 20}{190} ) = \frac{70}{190} - \frac{35}{190} = \frac{70 - 35}{190} = \frac{35}{190} = \frac{7}{38}$

$3) \frac{6}{12} + ( \frac{5}{12} - \frac{1}{12} ) = \frac{1}{2} + ( \frac{5 - 1}{12} ) = \frac{1}{2} + \frac{4}{12} = \frac{1}{2} + \frac{1}{3} = \frac{3 + 2}{6} = \frac{5}{6}$

$4) \frac{121}{300} - ( \frac{10}{300} + \frac{90}{300} ) = \frac{121}{300} - ( \frac{1}{30} + \frac{3}{10} ) = \frac{121}{300} - ( \frac{1 + 9}{30} ) = \frac{121}{300} - \frac{10}{30} = \frac{121}{300} - \frac{1}{3} = \frac{121 - 100}{300} = \frac{21}{300} = \frac{7}{100}$

$5) \frac{43}{100} - ( \frac{25}{100} + \frac{17}{100} ) = \frac{43}{100} - ( \frac{1}{4} + \frac{17}{100} ) = \frac{43}{100} - ( \frac{25 + 17}{100} ) = \frac{43}{100} - \frac{42}{100} = \frac{43}{100} - \frac{21}{50} = \frac{43 - 42}{100} = \frac{1}{100}$