Question

(1/14+2/21) *(5 1/2-2 1/14)

Answer 1

$\displaystyle \Big(\frac{1}{14}^{(3}+\frac{2}{21}^{(2}\ \Big)\cdot \Big(5\frac{1}{2}-2\frac{1}{14}\Big)=\frac{1\cdot 3+2\cdot 2}{42}\cdot \Big(\frac{11}{2}^{(7}-\frac{29}{14}^{(1}\ \Big)=\frac{7}{42}\cdot\frac{11\cdot 7-29}{14}=\\\\\\=\frac{1}{6}\cdot \frac{77-29}{14} =\frac{1}{6}\cdot \frac{48}{14}=\frac{1}{6}\cdot \frac{24}{7}=\frac{4}{7}$

Answer 2

Пошаговое объяснение:

$( \frac{1(3)}{14(3)} + \frac{2(2)}{21(2)} ) \times (5 \frac{1(7)}{2(7)} - 2 \frac{1}{14}) = ( \frac{3}{42} + \frac{4}{42}) \times (5 \frac{7}{14} - 2 \frac{1}{14}) = \frac{7}{42} \times 3 \frac{6}{14} = \frac{1}{6} \times 3 \frac{3}{7} = \frac{1}{6} \times \frac{24}{7} = \frac{4}{7}$