Question

8x^2+2x- 3=0 найдите сумму и произведение корней уравнения
pl

Answer 1

-0,25

Пошаговое объяснение:

$8x^2 + 2x - 3 = 0\\D = 2^2 - 4*8 * (-3) = 4 + 96 = 100\\x_{1} = \frac{-2-\sqrt{D} }{2*8} = \frac{-2-10}{16} = -\frac{12}{16} = -\frac{3}{4}\\x_{2} = \frac{-2+\sqrt{D} }{2*8} = \frac{-2+10}{2*8} = \frac{8}{2*8} = \frac{1}{2} \\S(x_1+x_2} = -\frac{3}{4} + \frac{1}{2} = -\frac{3}{4} + \frac{2}{4} = -\frac{1}{4} = -0.25$