ответ:Help translate the text from Russian into English (according to the rules as expected) without a translator.
I do not know how to get to the airport in my city, because I have never flown to other cities and countries.
I know how to get to the station (a month ago I went to my grandmother alone). If you go from my house, then you need to take a minibus 40 minutes. When the final stop is reached, you need to take bus 2 (it takes about 2 hours). This bus goes straight to the station (you just have to climb the stairs and go down to the station. There they will check bags on a special device.
to the bookstore account. We only have a library. It takes half an hour to get to the bookstore. Just take our minibus and stop near the bank. on the right side there will be a "globe" store where I always buy books
Пошаговое объяснение: Help translate the text from Russian into English (according to the rules as expected) without a translator.
I do not know how to get to the airport in my city, because I have never flown to other cities and countries.
I know how to get to the station (a month ago I went to my grandmother alone). If you go from my house, then you need to take a minibus 40 minutes. When the final stop is reached, you need to take bus 2 (it takes about 2 hours). This bus goes straight to the station (you just have to climb the stairs and go down to the station. There they will check bags on a special device.
to the bookstore account. We only have a library. It takes half an hour to get to the bookstore. Just take our minibus and stop near the bank. on the right side there will be a "globe" store where I always buy books
1. В 1 очередь надо найти область определения
Для левой части это будет x ≠ 2, ее же в этом случае приведем к виду
log√3=log√3
В правой части область определения x ≠ 2 и (x+1)/(x+2)>0, если x+1 >0 то и подавно x+2>0, если х+1 < 0 и x+2 <0, то x< -2, тогда x∈(-∞,-2)∪(-1,+∞), но с учетом x ≠2 имеем область определения x∈(-∞,-2)∪(-1,2)∪(2,+∞)
Теперь, избавляясь от логоарифмов
1/2= (x+1)/(x+2), x+2=2x+2
x =0
2. Тоже сначала ищем область определения
x²-9 ≥0, x ∈(-∞,-3]∪[3,+∞)
x+3 ≥ 0, x ∈ [-3,+∞)
x²+6x+9=(x+3)²≥0 ∀ x
Область определения в этом случае имеет вид x ∈ [3,+∞)
тогда имеем уравнение
+
≥x+3
+1 ≥
x-3+2+1≥x+3
2≥5
x-3 ≥ 6,25
x ≥ 9,25
3. x=2y
x-y=y, x-y+1=y+1
4y +
4y=0
4y=1,
y=0,25, x=0,5
Пошаговое объяснение:
Пошаговое объяснение:
№1
1) 3х-8=4
3х=4 +8
3х=12
х= 12:3
х= 4
2) 4(х-5)=5-х
4х-20= 5-х
4х+х= 5+20
5х= 25
х= 25 : 5
х= 5
№2
(х+2)/4-1= (3х+4)/12- х/6
3(х+2)- 1*12= 3х+4 - 2х
3х+6-12= 3х+4-2х
3х-3х+2х= 4-6+12
2х= 10
х= 10 : 2
х= 5
№3
4*|x-3|=52
4(х-3)= 52 4(х-3)= -52
4х-12= 52 4х-12= -52
4х= 52 +12 4х= -52 +12
4х= 64 4х= -40
х= 64 : 4 х= -40 : 4
х₁= 16 х₂= - 10
№4
Пусть на первой полке - х книг , тогда на второй - 3х книг, после того как на первую положили 4 книги на ней стало х+4, а на второй взяли 16 на ней стало 3х-16
Составим уравнение:
3х-16= х+4
2х= 4+16
2х= 20
х= 20 : 2
х= 10 книг на первой полке
3х= 3*10= 30 книг на второй полке