Question

1) 2 /1/2*48-3/2/3: 1/18+5/5/12: 7/36=81/6/7 нужно решение. 2)13/1/2: 1/1/3+16/1/2*1/5/11+19/1/4: 4/25=154/7/16 нужно решение. напишите нужно !

Answer 1

1
$2 \frac{1}{2}*48-3 \frac{2}{3}: \frac{1}{18}+5 \frac{5}{12}: \frac{7}{36}= 81 \frac{6}{7}\\ \\ 1) 2 \frac{1}{2}*48= \frac{5}{2}* \frac{48}{1}= 120 \\ \\ 2)3 \frac{2}{3}: \frac{1}{18}= \frac{11}{3}* \frac{18}{1}= 66 \\ \\ 3)5 \frac{5}{12}: \frac{7}{36}= \frac{65}{12}* \frac{36}{7}= \frac{195}{7}= 27 \frac{6}{7} \\ \\ 4)120-66+27 \frac{6}{7}= 81 \frac{6}{7}$

2
$13 \frac{1}{2}:1 \frac{1}{3}+16 \frac{1}{2}*1 \frac{5}{11}+19 \frac{1}{4}: \frac{4}{25}=154 \frac{7}{16} \\ \\ 1)13 \frac{1}{2}:1 \frac{1}{3}= \frac{27}{2}* \frac{3}{4}= \frac{81}{8}= 10 \frac{1}{8} \\ \\ 2)16 \frac{1}{2}*1 \frac{5}{11}= \frac{33}{2}* \frac{16}{11}= 24 \\ \\ 3) 19 \frac{1}{4}: \frac{4}{25}= \frac{77}{4}* \frac{25}{4} = \frac{1925}{16} =120 \frac{5}{16} \\ \\ 4)10 \frac{1}{8}+24+120 \frac{5}{16}=(10+24+120)+( \frac{1}{8}+ \frac{5}{16} )=154\frac{7}{16}$