Question

Как решить? 11 1/3: ((1 11/14-4 5/7)*4 2/ 5/6+3 2/9)*9/25

Answer 1

$11 \frac{1}{3}:((1 \frac{11}{14}-4 \frac{5}{7})*4 \frac{2}{3}-(-1 \frac{5}{6}+3 \frac{2}{9})* \frac{9}{25})=$$\frac{34}{3}:((\frac{25}{14}-\frac{33}{7})*\frac{14}{3}-(\frac{29}{9}-\frac{11}{6})* \frac{9}{25})=$$\frac{34}{3}:(\frac{25-33*2}{14}*\frac{14}{3}-\frac{29*2-11*3}{18}* \frac{9}{25})=$$\frac{34}{3}:(-\frac{41}{14}*\frac{14}{3}-\frac{25}{18}* \frac{9}{25})=$$\frac{34}{3}:(-\frac{41}{3}-\frac{1}{2})=\frac{34}{3}:(-\frac{85}{6})=\frac{34}{3}*(-\frac{6}{85})=\frac{17*2}{3}*(-\frac{3*2}{17*5})=-\frac{2*2}{5}=$$- \frac{4}{5}$ 

1) $1 \frac{11}{14}-4 \frac{5}{7}=\frac{25}{14}-\frac{33}{7}=\frac{25-33*2}{14}=-\frac{41}{14}$
2) $-1 \frac{5}{6}+3 \frac{2}{9}=\frac{29}{9}-\frac{11}{6}=\frac{29*2-11*3}{18}=\frac{25}{18}$
3) $-\frac{41}{14}*4 \frac{2}{3}=-\frac{41}{14}*\frac{14}{3}=-\frac{41}{3}$
4) $\frac{25}{18}*\frac{9}{25}= \frac{9}{18}= \frac{1}{2}$
5) $-\frac{41}{3}-\frac{1}{2} = -\frac{41*2+1*3}{6}=- \frac{85}{6}$
6) $11 \frac{1}{3}:(- \frac{85}{6} )=\frac{34}{3}*(-\frac{6}{85})=\frac{17*2}{3}*(-\frac{3*2}{17*5})=-\frac{2*2}{5}=- \frac{4}{5}$