Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue7Jdudi8x8c88s8w9e98r8c77s7st6seue745rğ
Пошаговое объяснение:
Djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker djoker
См рисунок
и
![x \in \: (- \infty ; \: 1] \: \cup \: [7; \: + \infty )](/tpl/images/1853/9951/0b25b.png)
Пошаговое объяснение:
1) Построим график функции.
Графиком функции является парабола, ветви вверх.
Парабола пересекает Ох в точках (1; 0) и (7; 0)
График приведен на рисунке.
По поводу неравенства:
Неравенство нестрогое - поэтому граничные точки включаются в решение. На графике видно, что неравенству удовлетворяют те части параболы, которые находятся НАД осью Ох. Включая и сами точки, в которых значенте функции равно нулю.
На рисунке часть графика НЕ удовлетворяющая неравенству обозначена красным.
Синий цвет графика - решение неравенства. Как видно, это 2 промежутка:
или же:
если сторона квадрата 6, то периметр 6*4=24, а площадь 6*6=36