Если чертить так, чтобы он делился чётко по целым числам, то минимальное число - 60 (клеточек), то есть 30 см.
Поэтому предлагаю начертить отрезок длиной 10 см,
1/3 * 10 (приблизительно) = 3,33 см
3/4 * 10 = 7,5 см
5/5 * 10=1*10= 10 см
7/5 * 10= 14 см
ответ: власна шв.човна 9км/год , швидкість течії 3 км/год .
Пошаговое объяснение:
Нехай х км/год - швидкість за течією , а у км/год - шв. проти течії
Система :
{ 2x + 3y = 42 , │X 2
{ 3x + 2y = 48 ; │ X ( - 3 )
{4x + 6y = 84 ,
{- 9x - 6y = - 144 ;
- 5x = - 60 ;
x = 12 .
Із 2-го рівняння 1-ої системи 3*12 + 2у = 48 ; 2у = 48 - 36 ; 2у = 12 ; у =6.
Отже , шв. за течією 12 км/год , а шв. проти течії 6 км/год .
Швидкість течії : ( 12 - 6 ) : 2 = 3 ( км/год ) , а власна шв.човна
12 - 3 = 9 ( км/год ) .
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Пошаговое объяснение:
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начертим отрезок 6см
длина второго= 6 * 1/3=2см
длина третьего= 6* 3/4=4,5см
длина четвертого= 6 *5/5=6 см (т.к 5/5-=1)
длина пятого = 6 * 7/6= 7см