Question

(3/4)^х-3 ≤ (4/3)^2x+5 решить неравенство у меня экзамен,

Answer 1

$(\frac{3}{4})^{x-3}\leq(\frac{4}{3})^{2x+5}\\((\frac{4}{3})^{-1})^{x-3}\leq(\frac{4}{3})^{2x+5}\ \textless \ =\ \textgreater \ (\frac{4}{3})^{3-x}\leq(\frac{4}{3})^{2x+5}\\3-x\leq2x+5\\-2\leq3x\\-\frac{2}{3}\leq x\ \textless \ =\ \textgreater \ x \geq-\frac{2}{3}$

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где $a=-\frac{2}{3}$, $\beta=0$;
x∈[$-\frac{2}{3}$; +∞)