(5х-2)^2-(3х-2)*(3х+2) при х=-0,1 нужно )

Question

Математика: (5х-2)^2-(3х-2)*(3х+2) при х=-0,1 нужно )

SadDorry · Accepted Answer

A) - (a-5)(a+-a)^2= - (a^2+3a-5a-15)- (1-2a+a^2) = - (a^2 -2a+15 -2a+a^2)= - a^2 +2 a - 15 -1+2a -a^2 = -2a^2 + 4a -16= -2 ( a^2 -2 a +8 ) c ) ( 2 a+ 0.5)^2 - ( 0.5 - 2 a )^2 = ( 0.5 + 2 a )^2 - ( 0 . 5 - 2 a )^2= 0.25 +2 a + 4 a ^2 - 0.25+ 2 a - 4 a^2= 4 a . e ) 25 x ^2 +( 7+5 x) (7-5x )= 25x^2 + 49-25x^2=49...

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