Question

Решите разложить на множители: 7-b√7= √12+√15= 7-4y²= выражение: 10√3-4√48-√75= (5√2-√18)×√2= (3-√2)²=

Answer 1

$7-b\sqrt{7}=\sqrt{7}(\sqrt{7}-b)\\\sqrt{12}+\sqrt{15}=\sqrt{3}(\sqrt{4}+\sqrt{5})\\7-4y^2=(\sqrt{7}-2y)(\sqrt{7}+2y)\\\\10\sqrt{3}-4\sqrt{48}-\sqrt{75}=10\sqrt{3}-16\sqrt{3}-5\sqrt{3}=-11\sqrt{3}\\(5\sqrt{2}-\sqrt{18})\sqrt{2}=5*2-\sqrt{18*2}=10-6=4\\(3-\sqrt{2})^2=11-6\sqrt{2}$

Answer 2

=√7(√7-b)
=√3(√4+√5)=√3(2+√5)
=

=10√3-4√(3·16)-√(25·3)=10√3-16√3-5√3= -11√3
=5·2-√(18·2)=10-√36=10-6=4
= 9-2·3·√2+2=11-6√2