Question

4целых5 11 +(8целых9 11-5целых7 11)-3целых8 11+1целая 3 11

Answer 1

$4\frac{5}{11}+(8\frac{9}{11}-5\frac{7}{11})-3\frac{8}{11}+1\frac{3}{11}=5\frac{2}{11}$

1) $8\frac{9}{11}-5\frac{7}{11}=\frac{97}{11}-\frac{62}{11}=\frac{97-62}{11}=\frac{35}{11}=3\frac{2}{11}$

2) $4\frac{5}{11}+3\frac{2}{11}=\frac{49}{11}+\frac{35}{11}=\frac{49+35}{11}=\frac{84}{11}=7\frac{7}{11}$

3) $7\frac{7}{11}-3\frac{8}{11}=\frac{84}{11}-\frac{41}{11}=\frac{84-41}{11}=\frac{43}{11}=3\frac{10}{11}$

4) $3\frac{10}{11}+1\frac{3}{11}=\frac{43}{11}+\frac{14}{11}=\frac{43+14}{11}=\frac{57}{11}=5\frac{2}{11}$

Answer 2

4 5/11+(8 9/11-5 7/11)-3 8/11+1 3/11=4 5/11+3 2/11-3 8/11+1 3/11=7 7/11-3 8/11+1 3/11=3 10/11+1 3/11=5 2/11