Question

Уравнение решить (1,7-1,8y)(6y+3)=0

Answer 1

1) 1,7-1,8y=0; 1,8y=1,7; y=17/18;
2) 6y+3=0; 6y=-3; y=-0,5;
ответ: y1=17/18, y2=-0,5

Answer 2

Решение: 

$(1.7-1.8y)*(6y+3)=0 = ( \frac{17}{10} - \frac{18}{10}y)*(6y3) = 0$

= $(\frac{17}{10} - \frac{9}{5}y)*(6y+3)=0$

= $\frac{17}{10} - \frac{9}{5}y = 0$

=$6y+3=0$

ответ:

$y1 = - \frac{1}{2}$
$y2= \frac{17}{18}$