Решите уравнение 5 sin^2 x + 3sinx × cosx - 2cos^2 x = 3 - id677787720220205 от ryzhovaelena1 05.02.2022 05:47

Question

Математика: Решите уравнение 5 sin^2 x + 3sinx × cosx - 2cos^2 x = 3

ryzhovaelena1 · Accepted Answer

А) 0,8 - 5/7 = 8/10 - 5/7 = 8/10 * 7 - 5/7 * 10 = 56/70 - 50/70 = 6/70 : 2 = 3/35
б) 0,5 +1/3 = 5/10 + 1/3 = 5/10 * 3 + 1/3 * 10 = 15/30 + 10/30 = 25/30 : 5 = 5/6
в) 7/8 - 0,25 = 7/8 - 25/100 : 25 = 7/8 - 1/4 = 7/8 -1/4 * 2 = 7/8 - 2/8 = 5/8
г) 0,4 + 0,67 = 4/10 + 67/100 = 4/10 * 10 + 67/100 = 40/100 + 67/100 = 107/100 = 1 цел 7/100
д) 0,5 +1/3 = 5/10 + 1/3 = 5/10 * 3 + 1/3 * 10 = 15/30 + 10/30 = 25/30 : 5 = 5/6
е) 1/3 - 0,25 = 1/3 - 25/100 : 25 = 1/3 - 1/4 = 1/3 * 4 - 1/4 * 3 = 4/12 - 3/12 = 1/12
ж) 0,125 + 5/12 = 125/1000 + 5/12 = 125/1000 : 125 + 5/12 = 1/8 + 5/12 = 1/8 * 3 + 5/12 * 2 = 3/24 + 10/24 = 13/24
з) 3/16 + 1/4 = 3/16 + 1/4 * 4 = 3/16 + 4/16 = 7/16

Решите уравнение 5 sin^2 x + 3sinx × cosx - 2cos^2 x = 3

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