Условие см. в приложении.
------------------------------------------------
1) х/4 = 5 2) 105/y = 7 3) (x + 12)/6 = 14
x = 5 * 4 y = 105 : 7 х + 12 = 14 * 6
x = 20 y = 15 x + 12 = 84
20 : 4 = 5 105 : 15 = 7 х = 84 - 12
5 = 5 7 = 7 х = 72
(72 + 12) : 6 = 14
84 : 6 = 14
14 = 14
х=1:6/7
х=7/6
х=1 1/6
у*11/16=1
у=1:11/16
у=16/11
у=1 5/11
у*32/35=1
у=1:32/35
у=35/32
у=1 3/32