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dkv1
dkv1
02.12.2022 13:10 •  Математика

Найдите неизвестный член пропорции. в.0,25/x=0,05/9 к.0,9/15=0,3/x р.4,8/x=1,6/7 о.11,5/6,9=x/27,6 э.x/1,9=66,5/13,3 т.1,2/2=x/0,2

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Ответ:
Divona2003
Divona2003
02.12.2022
В. 0,25/х = 0,05/9                 К. 0,9/15 = 0,3/х
х * 0,05 = 0,25 * 9                 0,9 * х = 15 * 0,3
х * 0,05 = 2,25                       0,9 * х = 4,5
х = 2,25 : 0,05                        х = 4,5 : 0,9
х = 45                                     х = 5

Р. 4,8/х = 1,6/7                       О. 11,5/6,9 = х/27,6
х * 1,6 = 4,8 * 7                      6,9 * х = 11,5 * 27,6
х * 1,6 = 33,6                          6,9 * х = 317,4
х = 33,6 : 1,6                           х = 317,4 : 6,9
х = 21                                      х = 46

Э. х/1,9 = 66,5/13,3                 Т. 1,2/2 = х/0,2
х * 13,3 = 1,9 * 66,5                 2 * х = 1,2 * 0,2
х * 13,3 = 126,35                      2 * х = 0,24
х = 126,35 : 13,3                       х = 0,24 : 2
х = 9,5                                       х = 0,12
4,4(71 оценок)
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Ответ:
foma199999
foma199999
02.12.2022
X:     \frac{9}{10} = 1 x  ·    \frac{10}{9} = 1 \frac{10}{9}x = 1 x =  \frac{9}{10} (x = 0.9) x : 19 =    \frac{16}{19} \frac{x}{19} = \frac{16}{19} x = 16 x : 3 =    \frac{5}{9}  \frac{x}{3} =  \frac{5}{9}  9x = 15 x =  \frac{5}{3} (x = 1 \frac{2}{3}, x  ≈ 1.66667) x  · \frac{1}{4}x = 4 \frac{1}{4}x = 4 x = 16 x :     \frac{7}{13} = 1 x  ·    \frac{13}{7} = 1 \frac{13}{7}x = 1 x = \frac{7}{13} x :     \frac{2}{18} = 18 x  ·    \frac{18}{2} = 18 x  · 9 = 18 9x = 18 x = 2 x : 10 =    \frac{1}{25}    \frac{x}{10}  =  \frac{1}{25}  25x = 10 x =    \frac{2}{5} (x = 0.4) x :     \frac{3}{10} =2 x  ·    \frac{10}{3} = 2 \frac{10}{3}x = 2 x =    \frac{3}{5}  (x = 0.6)
4,4(50 оценок)
Ответ:
astasevbogdanp08dn2
astasevbogdanp08dn2
02.12.2022

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4,7(20 оценок)
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