4класс ((2010-х): 3+31): 25+211=239

Question

Математика: 4класс ((2010-х): 3+31): 25+211=239

АртемкаЧеловечек · Accepted Answer

Solve for y: 11/6-(y+2/3) = 3/2 Put each term in y+2/3 over the common denominator 3: y+2/3 = (3 y)/3+2/3: 11/6-(3 y)/3+2/3 = 3/2 (3 y)/3+2/3 = (3 y+2)/3: 11/6-1/3 (3 y+2) = 3/2 Put each term in 11/6-(3 y+2)/3 over the common denominator 6: 11/6-(3 y+2)/3 = 11/6+(2 (-2-3 y))/6: 11/6+(2 (-2-3 y))/6 = 3/2 11/6+(2 (-2-3 y))/6 = (11+2 (-2-3 y))/6: (11+2 (-2-3 y))/6 = 3/2 2 (-2-3 y) = -6 y-4: (-4-6 y+11)/6 = 3/2 Grouping like terms, -(6 y)-4+11 = (11-4)-6 y: ((11-4)-6 y)/6 = 3/2 11-4 = 7: (7-6 y)/6 =...

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