Question

Решите неравенство : 1) 3x+7> 13. 2) 5x-15> 0. 3) 16-4x< 0. 4) 6(x+1)> 5x+3. решите неравенство: 1) -3< 1+2x< 4. 2) 1< 3-x< 5.

Answer 1

3x>6
x>2
x∈(-беск;2)
5x>15
x>3
x∈(-беск;3)
4x>16
x>4
x∈(-беск;4
6x+6>5x+3
x>-3
x∈(-беск;-3

Answer 2

1)$3x+7\ \textgreater \ 13$
$3x\ \textgreater \ 6$
$x\ \textgreater \ \frac{6}{3}$
$x\ \textgreater \ 2$
2)$5x-15\ \textgreater \ 0$
$5x\ \textgreater \ 15$
$x\ \textgreater \ \frac{15}{5}$
$x\ \textgreater \ 3$
3)$16-4x\ \textless \ 0$
$4x\ \textgreater \ 16$
$x\ \textgreater \ \frac{16}{4}$
$x\ \textgreater \ 4$
4)$-3\ \textless \ 1+2x\ \textless \ 4$
$-4\ \textless \ 2x\ \textless \ 4$
$-2\ \textless \ x\ \textless \ 2$
5)$1\ \textless \ 3-x\ \textless \ 5$
$-2\ \textless \ -x\ \textless \ 2$
$2\ \textgreater \ x\ \textgreater \ -2$
В 4 и 5 неравенствах я не уверен
Надеюсь