Question

Z= z1/ z2; комплексное число z1 =8 + i, z2 = 1 + 2i

Answer 1

$Z=\frac{Z_1}{Z_2}= \frac{8+i}{1+2i} = \frac{(8+i)(1-2i)}{(1+2i)(1-2i)} = \frac{8-16i+i-2i^2}{1-4i^2} = \frac{8-15i+2}{1+4} = \frac{10-15i}{5} =\\\\=2-3i$