Question

40 a) (1 18/25-9,12-7,4*(-6 1/3)): 5 1/3=

Answer 1

$1) \: \: 1 \frac{18}{25} - 9.12 = \frac{43}{25} - 9 \frac{12}{100} = \frac{43}{25} - 9 \frac{3}{25} = \frac{43}{25} - \frac{228}{25} = - \frac{185}{25} = - \frac{37}{5} \\ 2) \: \: 7.4 \times ( - 6 \frac{1}{3} ) = \frac{74}{10} \times ( - \frac{19}{3} ) = - \frac{37 \times 19}{5 \times 3} = - \frac{703}{15} \\ 3) - \frac{37}{5} - ( - \frac{703}{15} ) = - \frac{37}{5} + \frac{703}{15} = - \frac{111}{15} + \frac{703}{15} = \frac{592}{15} \\ 4) \: \: \frac{592}{15} \div 5 \frac{1}{3} = \frac{592}{15} \div \frac{16}{3} = \frac{592}{15} \times \frac{3}{16} = \frac{37}{5} = 7.4$
ответ: 7,4.

Answer 2

$\displaystyle \tt \bigg(1\frac{18}{25}-9,12-7,4\cdot \bigg(-6\frac{1}{3}\bigg)\bigg):5\frac{1}{3}=\bigg(1,72-9,12+\frac{74}{10}\cdot\frac{19}{3}\bigg)\cdot\frac{3}{16}=\\\\\\=\bigg(\frac{74}{10}\cdot\frac{19}{3}-\frac{74}{10}\bigg)\cdot\frac{3}{16}=\frac{74}{10}\cdot\frac{3}{16}\cdot \bigg(\frac{19}{3}-1\bigg)=\frac{74}{10}\cdot\frac{3}{16}\cdot\frac{16}{3}=\frac{74}{10}=7,4;$