Question

Сократите обыкновенные дроби (294-297) 2 и 6 3 и 9 4 и 12 5 и 25 6 и 48 10 и 90

Answer 1

$\displaystyle\tt\frac{2}{6}=\frac{1\cdot2}{3\cdot2}=\frac{1}{3};\\\\\\\frac{3}{9}=\frac{1\cdot3}{3\cdot3}=\frac{1}{3};\\\\\\\frac{4}{12}=\frac{1\cdot4}{3\cdot4}=\frac{1}{3};\\\\\\\frac{5}{25}=\frac{1\cdot5}{5\cdot5}=\frac{1}{5};\\\\\\\frac{6}{48}=\frac{1\cdot6}{8\cdot6}=\frac{1}{8};\\\\\\\frac{10}{90}=\frac{1\cdot10}{9\cdot10}=\frac{1}{9}$

Answer 2

$1)\frac{2}{6} = \frac{2 \div 2}{6 \div 2} = \frac{1}{ 3} \\ \\ 2) \frac{3}{9} = \frac{3 \div 3}{9 \div 3} = \frac{1}{3} \\ \\ 3) \frac{4}{12} = \frac{4 \div 4}{12 \div 4} = \frac{1}{ 3} \\ \\ 4) \frac{5}{25} = \frac{5 \div 5}{25 \div 5} = \frac{1}{5} \\ \\ 5) \frac{6}{48} = \frac{6 \div 6}{48 \div 6} = \frac{1}{8} \\ \\ 6) \frac{10}{90} = \frac{10 \div 10}{90 \div 10} = \frac{1}{9}$