2(х+2)-4(х-3)=5х+9 ста 4(3-х)-11=7(2х-5) 3)0,9(4у-2)=0,5(3у-4)+4,4

Question

Математика: 2(х+2)-4(х-3)=5х+9 ста 4(3-х)-11=7(2х-5) 3)0,9(4у-2)=0,5(3у-4)+4,4

марина1916 · Accepted Answer

1}}7 3/4- (4 5/6- 3 1/2)+ 1 2/3= 8 1/12 1)) 4 5/6- 3 1/2 = 4 5/6 - 3 (1•3)/(2•3)= 4 5/6 - 3 3/6= 1 2/6= 1 1/3 2)) 7 3/4 - 1 1/3= 7 (3•3)/(4•3) - 1 (1•4)/(3•4)= 7 9/12 - 1 4/12= 6 5/12 3)) 6 5/12+ 1 2/3= 6 5/12+ 1 (2•4)/(3•4)= 6 5/12+ 1 8/12= 7 13/12= 8 1/12 2}}9 2/5- (8 1/3- 7 1/4+ 5 1/6)= 3 3/20 1)) 8 1/3 - 7 1/4= 8 (1•4)/(3•4) - 7 (1•3)/(4•3)= 8 4/12 - 7 3/12= 1 1/12 2)) 1 1/12+ 5 1/6= 1 1/12+ 5 (1•2)/(6•2)= 1 1/12+ 5 2/12= 6 3/12= 6 1/4 3)) 9 2/5 - 6 1/4= 9 (2•4)/(5•4) - 6 (1•5)/(4•5)= 9 8/20...

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