Выражение 6(x+1)+2(x-1)(x^2+x+1)-2(x+1)^3 5x(x-3)^2-5(x-1)^3+15(x+2)(x-2) (x+2)^3-x(3x+1)^2+(2x+1)(4x^2-2x+1)

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Математика: Выражение 6(x+1)+2(x-1)(x^2+x+1)-2(x+1)^3 5x(x-3)^2-5(x-1)^3+15(x+2)(x-2) (x+2)^3-x(3x+1)^2+(2x+1)(4x^2-2x+1)

shahriyorchikozb8ts · Accepted Answer

1) 2 sin x + 1 = 0 2 sin x = -1 sin x = -1/2 x = (-1) ^ n * (- п/6) + пn 2) tg (3x - п) = 0 3x - п = пn 3x = пn + п х = пn/3 + п/3 3) 2 cos x + √3 = 0 2 cos x = - √3 Cos x = - √3/2 X = ±5π/6 + 2πn 4) 2 sin 2x = √3 Sin 2x = √3 / 2 2X = (-1)^n * π/3 + πn X = (-1)^n * π/6 + πn/2 5) sin x - √3 cos x = 0 2 sin (x- π/3) = 0 Sin (x - π/3) = 0 X - π/3 = πn X = π/3+ πn 6) tg 2x = 1 2x = π/4 + πn X = π/8 + πn/2 7) 2 sin x = 1 Sin x = ½ X = (-1)^n * π/6 + πn 8) 8 sin ^ 2 x – 10 sin x – 7 =0 Замена sin x =...

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