Question

а) √1225-√2116; б) 3√0,1024-√0,3136; в) 0,2√676+√23,04

Answer 1

$1)\sqrt{1225}-\sqrt{2116}=\sqrt{35^{2}}-\sqrt{46^{2}}=35-46=-11\\\\2)3\sqrt{0,1024}-\sqrt{0,3136}=3\sqrt{0,32^{2}}+\sqrt{0,56^{2}}=3*0,32-0,56=0,96-0,56=0,4\\\\3)0,2\sqrt{676}+\sqrt{23,04}=0,2\sqrt{26^{2} }+\sqrt{4,8^{2}}=0,2*26+4,8=5,2+4,8=10$