Question

Сократить выражение на логарифмы 56

Answer 1

$\frac{1+log_{x}^3y}{(log_{y}x+log_{x}y-1)\cdot log_{x}(xy)}=\frac{(1+log_{x}y)(log_{x}^2y-log_{x}y+1)}{(log_{x}y+\frac{1}{log_{x}y}-1)\cdot (log_{x}x+log_{x}y)}}=\\\\\\=\frac{(1+log_{x}y)(log_{x}^2y-log_{x}y+1)}{\frac{log_{x}^2y-log_{x}y+1}{log_{x}y}\cdot (1+log_{x}y)}}=\frac{log_{x}y\cdot (log_{x}^2y-log_{x}y+1)}{log_{x}^2y-log_{x}y+1}=log_{x}y$

Answer 2

ответ:  во вложении Объяснение: