Question

2х^2+2х=5 через дискриминант​

Answer 1

$2x^{2} +2x=5\\\\2x^{2}+2x-5=0\\\\D=2^{2}-4*2*(-5)=4+40=44=(2\sqrt{11})^{2}\\\\x_{1}=\frac{-2-2\sqrt{11}}{4}=-\frac{1+\sqrt{11}}{2}\\\\x_{2}=\frac{-2+2\sqrt{11}}{4}=\frac{\sqrt{11}-1}{2}$

Answer 2

Объяснение:

$2x^2+2x=5\\2x^2+2x-5=0\\D=4-4*2*(-5)=44\\\\x_1=\frac{-2+2\sqrt{11} }{4} =1.15831\\x_2=\frac{-2-2\sqrt{11} }{4} =-2.15831$