Вычислите: 10*(5,8 - 3 целых 3/4) - id1100741720220108 от dejavu1337 08.01.2022 03:02

Question

Алгебра: Вычислите: 10*(5,8 - 3 целых 3/4)

dejavu1337 · Accepted Answer

1. 2x2+3x+19 = 0

D= b2 - 4ac

D=9 - 4*2·19 = -143

2. 26х2+5х+10=0

D= b2 - 4ac

D= 25 - 4*26*10 = -1015

D<0 корней нет

3. x2+8x+15=0

D= b2 -4ac

D= 64 - 4*15= 4

x1= -b+√D / 2a = -8 +2 / 2*1 = -6/2 = -3

x2= -b - √D / 2a = -8 - 2 / 2*1 = -10/2 = -5

4. 4x2−14x+6=0

D= b2 - 4ac

D= 196 - 4*4*6 = 100

x1= -b+√D / 2a = 14 + 10 / 2*4 = 24/8 = 3

x2= -b - √D / 2a = 14 -10/ 2*4 = 4/8 = 1/2

5. 6x2+6x+15=0

D= b2 - 4ac

D= 36 - 4*6*15 = -324

6. 2x2+19x+1=0

D= b2 - 4ac

D= 361 - 4*2*1 = 353

D>0 2 корня

7. x2+8x+16=0

D= b2 - 4ac

D= 64 - 4*16 = 0

x= -b+ √D / 2a = -8+0 / 2*1 = -8/2 = -4

8. 2x2−7x+6=0

D= b2 - 4ac

D= 49 - 4*2*6 = 1

x1= -b+√D / 2a = 7 +1/ 2*2 = 8/4 = 2

x2= -b - √D / 2a = 7 -1/ 2*2 = 6/4 = 3/2 = 1 1/2

Вычислите: 10*(5,8 - 3 целых 3/4)