Question

вычислить. не ответ, а с решением!

Answer 1

$\frac{\left(\sqrt[3]{\sqrt[5]{2}}\right)^{30}}{40}\\\left(\sqrt[3]{\sqrt[5]{2}}\right)^{30} =\left(\left(\sqrt[5]{2}\right)^{\frac{1}{3}}\right)^{30} =\left(\sqrt[5]{2}\right)^{\frac{1}{3}\cdot \:30}=\left(\sqrt[5]{2}\right)^{10}=\left(2^{\frac{1}{5}}\right)^{10}=2^{\frac{1}{5}\cdot \:10}=2^2=4\\\frac{\left(\sqrt[3]{\sqrt[5]{2}}\right)^{30}}{40}=\frac{4}{40}=\frac{1}{10}=0,1$

$\sqrt[4]{\left(\frac{1}{2}\right)^{12}}=\left(\frac{1}{2}\right)^{\frac{12}{4}}=\left(\frac{1}{2}\right)^3=\frac{1}{8}=0,125$

$\left(2^{\sqrt{2}}\right)^{\sqrt{8}} = 2^{\sqrt{2}\sqrt{8}} = 2^{2\sqrt{2}\sqrt{2}}=2^4=16$