Question

Найдите производные функции 1) у=8 под корнем х- 12/x+16x4 ; 2) y=11+2x/x-1

Answer 1

1) $y = 8\sqrt{x}-\frac{12}{x}+16x^4$

$y' = -\frac{8}{2\sqrt{x}}+\frac{12}{x^2}+64x^3 = 4(16x^3+\frac{3}{x^2}-\frac{1}{\sqrt{x}})$ 

2) $y = 11 + \frac{2x}{x-1}$

$y' = \frac{2(x-1)-2x}{(x-1)^2} = -\frac{2}{(x-1)^2}$