Cos(5π/2+α),если sinα=0,5

Question

Алгебра: Cos(5π/2+α),если sinα=0,5​

МарияLevkivska · Accepted Answer

1) sinx = -1/2; x = (-1)^(n+1)* arcsin(|-1/2|) + pi*n; x = (-1)^(n+1)* pi/6) + pi*n; n ∈ Z n = 0; x = -pi/6 ∉[0;3p] n = 1; x = pi/6 + pi = 7pi/6 ∈[0;3p] n = 2; x = -pi/6 + 2pi = 11pi/6  ∈[0;3p] n = 3; x = pi/6 + 3pi ∉[0;3p] ответ:  x = 7pi/6 ∪ x = 11pi/6 2)  sinx = 1/2; x = (-1)^(n)* arcsin1/2) + pi*n; x = (-1)^(n)* pi/6)+ pi*n; n ∈ Z n = -1; x = -pi/6 - pi ∉ [-p/2;3p/2] n = 0; x = pi/6 ∈[-p/2;3p/2] n = 1; x = -pi/6 + pi = 5pi/6 ∈[-p/2;3p/2] n = 2; x = pi/6 + 2pi ∉[-p/2;3p/2] ответ:  x = pi/6 ∪ x...

Cos(5π/2+α),если sinα=0,5​

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