(х² - 1)² + (х - 1) = 0
((x - 1)(x + 1))² + (x - 1) = 0
(x - 1)*((x - 1) * (x + 1)² + 1) = 0
x - 1 = 0 (x - 1) * (x + 1)² + 1 = 0
x = 1 (x - 1) * (x² + 2x + 1) + 1 = 0
x³ + 2x² + x - x² - 2x - 1 + 1 = 0
x³ + x² - x = 0
x(x² + x - 1) = 0
x = 0 x² + x - 1 = 0
D = 1² + 4 * 1 * 1 = 5
x = (-1 - √5)/2
x = (-1 + √5)/2
ответ: 
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