Question

Найдите область определения функции.

Answer 1

Объяснение:

ОДЗ:

$\left\{\begin{array}{ccc}x^2-4x\geq 0\\25-x^2\geq 0\\x^2-1\neq0 \end{array}\right;\left\{\begin{array}{ccc}x*(x-4)\geq 0\\(5+x)*(5-x)\geq 0 \\(x+1)*(x-1)\neq0 \end{array}\right\\x*(x-4)\geq 0\\$

-∞__+__0__-__4__+__+∞

$x\in(-\infty;0]U[4;+\infty).\\(5+x)*(5-x)\geq 0\\$

-∞__-__-5__+__5__-__+∞

$x\in[-5;5].\\(x+1)*(x-1)\neq 0\\x_1\neq -1;x_2\neq 1.\\\left\{\begin{array}{ccc}x\in(-\infty;0]U[4;+\infty)\\x\in[-5;5]\\x_1\neq -1;x_2\neq 1.\end{array}\right \\$

ОДЗ: x∈[-5;-1)U(-1;0]U[4;5].