Question

Обчисліть

4sinL-cosL/cosL+4sinL

Якщо ctgL=1/3

Answer 1

Первый

$\frac{4Sin\alpha-Cos\alpha}{Cos\alpha+4Sin\alpha} =\frac{\frac{4Sin\alpha}{Sin\alpha}-\frac{Cos\alpha}{Sin\alpha}}{\frac{Cos\alpha}{Sin\alpha}+\frac{4Sin\alpha}{Sin\alpha}}=\frac{4-Ctg\alpha}{Ctg\alpha+4}=\frac{4-\frac{1}{3}}{\frac{1}{3}+4}=\frac{3\frac{2}{3}}{4\frac{1}{3}}=\frac{11}{3}*\frac{3}{13}=\frac{11}{13}$

Второй

$Ctg\alpha =\frac{1}{3}\\\\\frac{Cos\alpha}{Sin\alpha}=\frac{1}{3} \Rightarrow Sin\alpha=3Cos\alpha\\\\\frac{4Sin\alpha-Cos\alpha}{Cos\alpha+4Sin\alpha}=\frac{4*3Cos\alpha-Cos\alpha}{Cos\alpha+4*3Cos\alpha}=\frac{11Cos\alpha}{13Cos\alpha}=\frac{11}{13}$

Answer 2

Объяснение:

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