Consider the remainders when dividing by 12. Which of them will be included in the group of multiplying - id1358315220220514 от maritsumie 14.05.2022 17:22

Question

Алгебра: Consider the remainders when dividing by 12. Which of them will be included in the group of multiplying the remainders when divided by 12? Answer:Multiple Solutions are from 1 to 11

maritsumie · Accepted Answer

А) 4*√(k+6)=k+1 возводим в степень, записав ОДЗ k>=-1
16*(k+6)=k^2+2*k+1 16*k+96=k^2+2*k+1 k^2-14*k-95=0
k1,2=(14±24)/2 k1=-5 - не отвечает ОДЗ, k2=19
Б) √(12-k)=k,ОДЗ 0=<k=<12 возводим в степень 12-k=k^2 k^2+k-12=0 k1,2=(-1±7)/2 k1=-4 - не отвечает ОДЗ, k2=3
В) с-5=√(с+1) ОДЗ с>=5
c^2-10*c+25=c+1 c^2-11*c+24=0 c1,2=(11±5)/2 c1=3 - не отвечает ОДЗ с2=8
Г) √(4-y)=y+2 ОДЗ -2=<y=<4
4-y=y^2+4*y+4 y^2+5*y=0 y*(y+5)=0 y1=0 y2=-5 - не отвечает ОДЗ
Д) √(2*a-7)=a-21 ОДЗ a>=21
2*a-7=a^2-42*a+441 a^2-44*a+448=0 a1,2=(44±12)/2 a1=16 - не отвечает ОДЗ a2=28
Е) √(f-2)=f-4 ОДЗ f>=4 f-2=f^2-8*f+16 f^2-9*f+18=0 f1,2=(9±3)/2 f1=3 -не отвечает ОДЗ f2=6

Consider the remainders when dividing by 12. Which of them will be included in the group of multiplying the remainders when divided by 12? Answer:Multiple Solutions are from 1 to 11

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