![\left[\begin{array}{ccc}0&1&0\\0&0&1\\0&0&0\end{array}\right]](/tpl/images/0459/8733/0ef41.png)
![\left[\begin{array}{ccc}0&0&0\\1&0&0\\0&1&0\end{array}\right]](/tpl/images/0459/8733/bed8c.png)
![\left[\begin{array}{ccc}0&0&1\\0&0&0\\0&0&0\end{array}\right]](/tpl/images/0459/8733/dec6f.png)
![\left[\begin{array}{ccc}0&0&0\\0&0&0\\1&0&0\end{array}\right]](/tpl/images/0459/8733/14fe4.png)
или![\left[\begin{array}{ccc}0&0&0\\1&0&0\\0&1&0\end{array}\right]](/tpl/images/0459/8733/f3b18.png)
(x - y)² + (x - y) - 2 = 0
x² + y² = 41
x - y = t
t² + t - 2 = 0
D = 1 + 8 = 9
t12=(-1 +- 3)/2 = 1 -2
(t + 2)(t - 1) = 0
(x - y - 1)(x - y + 2) = 0
1. x - y - 1 = 0
x = y + 1
(y + 1)² + y² = 41
2y² + 2y - 40 = 0
y² + y - 20 = 0
D = 1 + 80 = 81
y12=(-1 +- 9)/2 = -5 4
y=-5 x = y + 1 = -4
y = 4 x = y + 1 = 5
2. x - y + 2 = 0
x = y - 2
(y - 2)² + y² = 41
y² - 4y + 4 + y² = 41
2y² -4y -37 = 0
D = 16 + 4*2*37 = 312
y12 = (4 +- 2√78)/4 = 1 +- √(39/2)
x12 = -1 +- √(39/2)
ответ (-4, -5) (5,4) ( -1 + √(39/2), 1 +√(39/2)) ( -1 - √(39/2), 1 -√(39/2))
Объяснение:2tg²(π/3)= 2·(√3)²=2·3=6