Question

буду благодарен только минут дали я

Answer 1

№33.4

1)$(4x+0,1y)^{3} =64x^{3} +4\frac{4}{5} x^2y+\frac{3}{25} xy^{2} +\frac{1}{1000} y^{3} \\$

4)$(0,3b-10c)^{3} =\frac{27}{1000}b^{3} -2\frac{7}{10}b^{2} c+90bc^{2} -1000c^{3}\\$

2)$(0.2a+30b)^{3} =\frac{1}{125} a^{3} +3\frac{3}{5} a^{2} b+540ab^{2} +27000b^{3}$

5)$(0,5x-2y)^{3}=\frac{1}{8} x^{3}-1\frac{1}{2}x^{2} y+ 6xy^{2} -8y^{3}$

3)$(\frac{1}{7} a-7c)x^{3}=\frac{1}{343}a^{3}-\frac{3}{7} a^{2}c+21ac^{2} -343c^{3}$

6)$(\frac{2}{9}n +\frac{9}{2}m )^{3} =\frac{8}{729} n^{3} +\frac{2}{3} mn^{2} +13\frac{1}{2} m^{2} n+91\frac{1}{8}m^{3} \\$

№33.5

1)$(x^{3} -3x^{2} +x-1)=(x-1)^{3}$

3)$(8+12p+6x^{2} +x^{3} )=(p+2)^{3}$

5)$(125-75a+15a^{2} -a^{3})=-(a-5)^{3}$

2)$(y^{3} -3y^{2} +3y-1)=(y-1)^{3}$

4)$1-6q+12q^{2}-8q^{3} =-8*(q-\frac{1}{2})^{3} \\$

6)$0.008+12p+0.6p^{2} +p^3=(p+\frac{1}{5})^{3}$

вот