1/5 a²b³c, где a = -2, b = -1, c = 10. - id1668274820220129 от deniskalubit 29.01.2022 18:29

Question

Алгебра: 1/5 a²b³c, где a = -2, b = -1, c = 10.​

deniskalubit · Accepted Answer

1) 7tgx -10Ctgx +9 =0 |* tgx      7tg^2x -10 +9tgx = 0 tgx = y 7y^2 +9y -10 = 0 y1 = 10/14 = 5/7 у2 = -2 а) у = 5/7 tgx = 5/7 x = arctg5/7 + k, k ЄZ б) у = -2 tgx = -2 x = -arctg2 +k, k ЄZ 2) 10SinxCosx -14Cos^2x +2*1 = 0 10SinxCosx -14Cos^2x +2(Sin^2x+Cos^2x) = 0 10SinxCosx -14Cos^2x +2Sin^2x +2Cos^2x = 0 10SinxCosx -12Cos^2x +2Sin^2x = 0 :Cos^2x 10tgx -12 +2tg^2x= 0 tgx = y 2y^2 +10y -12=0 y^2 + 5y - 6 = 0 По т. Виета у1 = - 6 и  у2 = 1 а) у = - 6 tgx = -6 x = -arctg6+k, kЄZ  б)у = 1 tgx = 1 x...

1/5 a²b³c,где a = -2, b = -1, c = 10.​

MOGZ ответил

1/5 a²b³c,
где a = -2, b = -1, c = 10.