Question

нужно польностю решения можно

Answer 1

а)

${x}^{2} {y}^{2} - 16 = {(xy)}^{2} - {4}^{2} = \\ = (xy - 4)(xy + 4)$

б)

$36 - {a}^{2} {b}^{2} = {6}^{2} - (ab) {}^{2} = \\ = (6 - ab)(6 + ab)$

в)

${m}^{2} {n}^{2} - 0.09 = (mn) {}^{2} - {(0.3)}^{2} = \\ = (mn - 0.3)(mn + 0.3)$

г)

$\frac{16}{25} - {k}^{2} {p}^{2} = {( \frac{4}{5}) }^{2} - ( kp) {}^{2} = \\ = ( \frac{4}{5} - kp)( \frac{4}{5} + kp)$

д)

$0.81 {p}^{2} - 4 {a}^{2} {b}^{2} = {(0.9 p) }^{2} - (2ab) {}^{2} = \\ = (0.9 p - 2ab)(0.9 p + 2ab)$

е)

$9 {m}^{2} {n}^{2} - 0.01 {p}^{2} = (3 mn) {}^{2} - (0.1 p) {}^{2} = \\ = (3 mn - 0.1p)(3mn + 0.1p)$

ж)

$0.04 {k}^{2} - 0.09 {a}^{2} {n}^{2} = (0.2k) {}^{2} - (0.3an) {}^{2} = \\ = (0.2k - 0.3an)(0.2k + 0.3an )$

з)

$\frac{1}{9} {a}^{2} {b}^{2} - \frac{25}{9} {m}^{2} {p}^{2} = \\ = \frac{1}{9} ( (ab ) {}^{2} - (5 mp) {}^{2} ) = \\ = \frac{1}{9}( ab - 5mp)(ab + 5mp)$