Question

Log0.5 1/x + 4log0.5 x^(1/3)= -1 решить !

Answer 1

$\log_{0.5}\bigg( \dfrac 1x\bigg) + 4\log_{0.5}\Big(x^{\frac 13}\Big)=-1\\\\\log_{0.5}\Big(x^{-1}\Big) + \log_{0.5}\Big(x^{\frac 13}\Big)^4=-1\\\\\log_{0.5}\Big(x^{-1}\cdot x^{\frac 43}\Big)=-1\\\\\log_{0.5}\Big(x^{\frac 13}\Big)=-1\\\\x^{\frac 13}=\big(0,5\big)^{-1}$

$x^{\frac 13}=\bigg(\dfrac 12\bigg)^{-1}\\\\x^{\frac 13}=2~~~\big|~~()^3\\\\x=2^3~~~~~~~\boxed{\boldsymbol{x=8}}$

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Использованы формулы

$\log_ab+\log_ac=\log_a(bc)\\\\n\log_ab=\log_ab^n\\\\\log_ab=c~~~\Rightarrow~~~a^c=b$

Answer 2

8.

Объяснение:

$\log_{0,5}\frac{1}{x} +4\log_{0,5}x^{\frac{1}{3} } =-1;\\\\\log_{0,5}x^{-1} +\frac{4}{3} \log_{0,5}x=-1;\\\\-\log_{0,5}x+\frac{4}{3} \log_{0,5}x=-1 |*3;\\\\-3\log_{0,5}x+4\lg_{0,5}x=-3;\\\\\log_{0,5}x=-3;\\\\x=(0,5)^{-3} ;\\\\x=(\frac{1}{2} )^{-3} ;\\\\x=2^{3} ;\\\\x=8.$