Б) (x²-4x-4)² + 2(x-2)²=3 г) 2(x²+2x+1)²- (x+1)²=1 - id2065432120210907 от darionm 07.09.2021 07:48

Question

Алгебра: Б) (x²-4x-4)² + 2(x-2)²=3 г) 2(x²+2x+1)²- (x+1)²=1

darionm · Accepted Answer

1) 5x^2 - 15x - x - 3 =0Объяснение:1) D= b^2-4ac= 196+60= 256 = 16^2x1= -14+16/10= 1/5x2= - 14-16/10= - 32) D=25-16=9=3^2x1= 5+3/2=8/2=4x2= 5-3/2=2/2=13) 10x^2 + 5x-3/5=050x^2 +25x-3=0D= 625+600=1225=35^2x1= -25+35/100= 1/10x2= - 25-35/100= - 3/54) x^2 +6x-5x=0x^2+x=0D= 1=1^2x1= - 1+1/2=0x2= - 1-1/2=-15) 2-3x-5x^2=0-5x^2-3x+2=05x^2+3x-2=0D=40+9=49=7^2x1=-3+7/10= 2/5x2=-3-7/10= - 16) x^2-4x+4=3x-8x^2-4x+4-3x+8=0x^2-7x+12=0D=49-48=1=1^2x1=7+1/2= 4x2=7-1/2= 37) 5(x^2+4x+4)= -505x^2+20x+20= -505x^2+20x+20-50=05x^2+20x+70=0x^2+4x+14=0D=...

Б) (x²-4x-4)² + 2(x-2)²=3г) 2(x²+2x+1)²- (x+1)²=1

MOGZ ответил

Б) (x²-4x-4)² + 2(x-2)²=3
г) 2(x²+2x+1)²- (x+1)²=1