1) sin x = √2/2
x = (-1)ⁿ × arcsin √2/2 + πn, n∈Z
x = (-1)ⁿ × π/4 + πn, n∈Z
2) sin x = -√2/2
x = (-1)ⁿ × arcsin (-√2/2) + πn, n∈Z
x = (-1)ⁿ × -arcsin √2/2 + πn, n∈Z
x = (-1)ⁿ × (-π/4) + πn, n∈Z
3) sin x = -√3/2
x = (-1)ⁿ × arcsin (-√3/2) + πn, n∈Z
x = (-1)ⁿ × -arcsin √3/2 + πn, n∈Z
x = (-1)ⁿ × (-π/3) + πn, n∈Z
4) sin x = √3/2
x = (-1)ⁿ × arcsin √3/2 + πn, n∈Z
x = (-1)ⁿ × arcsin √3/2 + πn, n∈Z
x = (-1)ⁿ × π/3 + πn, n∈Z
5) sin x = 4/5
x = (-1)ⁿ × arcsin 4/5 + πn, n∈Z
x = (-1)ⁿ × 0,927295 + πn, n∈Z
x = (-1)ⁿ × 53,1° + πn, n∈Z
Вообще по формуле: logax-logay=loga(x/y)(a-основание)
Значит log6135−log63,75=log(6135/63,75)=log96,2