Question

Разложите на множители а)6a^2*(a--5)^2 б)(x+7)^3-8x^2*(x+7) в)n*(3n-4)^2+(3n-4)^3 г)4t*(4t-1)^2-(4t-1)^3 д)6a^2*(2a-5)^2-12a*(2a-5)*(a+5)^2 е)x^2*(x-3)*(3x+3)^2-4x^2*(x-3)^2 ж)t^2*(t+12)^3-t*(t+12)^2*(t-5)^2

Answer 1

1)(a-5)(6a²-(a-5))=(a-5)(6a²-a+5)
2)(x+7)((x+7)²-8x²)=(x+7)(x²+14x+49-8x²)=(x+7)(14x+49-7x²)=7(x+7)(2x+7-x²)
3)(3n-4)²(n+3n-4)=(3n-4)(4n-4)=4(3n-4)(n-1)
4)(4t-1)²(4t-4t+1)=(4t-1)²
5)6a(2a-5)(a(2a-5)-2(a+5)²)=6a(2a-5)(2a²-5a-2a²-20a-50)=6a(2a-5)(-25a-50)=                    =-150a(2a-5)(a+2)
6)9x²(x-3)(x+1)²-4x²(x-3)²=x²(x-3)(9(x+1)²-4(x-3))=x²(x-3)(9x²+18x+9-4x+12)=                 =x²(x-3)(9x²+14x+21)
7)t(t+12)²(t(t+12)-(t-5)²)=t(t+12)²(t²+12t-t²+10t-25)=t(t+12)²(22t-25)