Question

Преобразования с корнями. 1) 2) 3) 4) 5) 6) 7) расположите в порядке убывания:

Answer 1

$1)2\sqrt{2}*5\sqrt{3}*\sqrt{6}=10\sqrt{6}*\sqrt{6}=10*6=60\\ 2)\frac{\sqrt{50}*\sqrt{6}}{\sqrt{12}}=\frac{\sqrt{50}}{\sqrt{2}}=\sqrt{25}=5\\ 3)\frac{(3\sqrt{5})^2}{15}=\frac{9*5}{15}=3\\ 4)\frac{a\sqrt{35}}{\sqrt{5a}}=\frac{a\sqrt{7}}{\sqrt{a}}=\sqrt{7}*\sqrt{a}\\ 5)\frac{\sqrt{91ab}}{\sqrt{13a}} = \sqrt{7b}\\ 6) \sqrt{5.88}*\frac{1}{\sqrt{12}}=\sqrt{0.49}=0.7\\ 7)2\sqrt{21}=\sqrt{84}\\ 4\sqrt{5}=\sqrt{80}\\ 10\\ \\ 10,2\sqrt{21},4\sqrt{5}$