Question

Преобразуйте в многочлен стандартного вида 7x(3-x)+(6+2x)^2 (2b+3)^2-(2b-5)(2b+5)

Answer 1

$1)7x(3-x)+(6+2x) ^{2} =21x-7 x^{2} +36+4 x^{2} +24x= \\ \\ =-3 x^{2} +45x+36 \\ \\ \\ 2)(2b+3) ^{2} -(2b-5)(2b+5)=4b ^{2} +9+12b-4b ^{2} +25= \\ \\ =12b+34$

Answer 2

7x(3-x)+(6+2x)^2=21x-7x²+36+24x+4x²=-3x²+45x+36
(2b+3)^2-(2b-5)(2b+5) =4b²+12b+9-4b²+25=12b+34