Question

Sin(3π/14)-sin(π/14)-sin(5π/14)= ответ: -1/2 нужно !

Answer 1

$sin\frac{3\pi}{14}-sin\frac{\pi}{14}-sin\frac{5\pi}{14}=\\\\ -2sin\frac{\frac{2\pi}{14}}{2}*cos\frac{\frac{8\pi}{14}}{2}-sin\frac{\pi}{14} \\\\ -2sin\frac{\pi}{14}*cos\frac{2\pi}{7}-sin\frac{\pi}{14}=\\\\ -sin\frac{\pi}{14}(2cos\frac{2\pi}{7}+1)=\\\\ \frac{ 2cos\frac{\pi}{14}* -sin\frac{\pi}{14}(2cos\frac{2\pi}{7}+1)}{2cos\frac{\pi}{14}}=\\\\ \frac{-sin\frac{\pi}{7}*(2cos\frac{2\pi}{7}+1)}{ 2cos\frac{\pi}{14}} = \\\\$
теперь заметим что   
  $sin\frac{\pi}{7}*2cos\frac{2\pi}{7}+sin\frac{\pi}{7}=\\ cos\frac{\pi}{14}-cos\frac{5\pi}{14}+sin\frac{\pi}{7}=\\ cos\frac{5\pi}{14}=sin\frac{\pi}{7}\\ cos\frac{\pi}{14}-cos\frac{5\pi}{14}+sin\frac{\pi}{7}=cos\frac{\pi}{14}\\\\ \frac{-cos\frac{\pi}{14}}{2cos\frac{\pi}{14}}=-\frac{1}{2}$